Question
Find roots of polynomial $$ p(x) = 40y^2-324y+529 $$
Answer
The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= 5.8326\\[1 em]y_2 &= 2.2674 \end{aligned} $$Explanation
The solutions of $ 40y^2-324y+529 = 0 $ are: $ y = \dfrac{ 81 }{ 20 }-\dfrac{\sqrt{ 1271 }}{ 20 } ~ \text{and} ~ y = \dfrac{ 81 }{ 20 }+\dfrac{\sqrt{ 1271 }}{ 20 }$.
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