Question
Find roots of polynomial $$ p(x) = 3x-1+x^2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.3028\\[1 em]x_2 &= -3.3028 \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} 3x-1+x^2 & = 0\\[1 em] x^2+3x-1 & = 0 \end{aligned} $$Step 2:
The solutions of $ x^2+3x-1 = 0 $ are: $ x = -\dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 13 }}{ 2 } ~ \text{and} ~ x = -\dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 13 }}{ 2 }$.
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