Question
Find roots of polynomial $$ p(x) = 3x^2+9x-293 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 8.4958\\[1 em]x_2 &= -11.4958 \end{aligned} $$Explanation
The solutions of $ 3x^2+9x-293 = 0 $ are: $ x = -\dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 3597 }}{ 6 } ~ \text{and} ~ x = -\dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 3597 }}{ 6 }$.
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