Question
Find roots of polynomial $$ p(x) = 3x^2+27x-239 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 5.4958\\[1 em]x_2 &= -14.4958 \end{aligned} $$Explanation
The solutions of $ 3x^2+27x-239 = 0 $ are: $ x = -\dfrac{ 9 }{ 2 }-\dfrac{\sqrt{ 3597 }}{ 6 } ~ \text{and} ~ x = -\dfrac{ 9 }{ 2 }+\dfrac{\sqrt{ 3597 }}{ 6 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator