Question
Find roots of polynomial $$ p(x) = 3x^2-1637x-9508 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 551.4143\\[1 em]x_2 &= -5.7476 \end{aligned} $$Explanation
The solutions of $ 3x^2-1637x-9508 = 0 $ are: $ x = \dfrac{ 1637 }{ 6 }-\dfrac{\sqrt{ 2793865 }}{ 6 } ~ \text{and} ~ x = \dfrac{ 1637 }{ 6 }+\dfrac{\sqrt{ 2793865 }}{ 6 }$.
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