Question
Find roots of polynomial $$ p(x) = 3x^2-14+8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \sqrt{ 2 }\\[1 em]x_2 &= -\sqrt{ 2 } \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ 3x^2 \color{blue}{-14} + \color{blue}{8} = 3x^2 \color{blue}{-6} $$Step 2:
The solutions of $ 3x^2-6 = 0 $ are: $ x = -\sqrt{ 2 } ~ \text{and} ~ x = \sqrt{ 2 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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