Question
Find roots of polynomial $$ p(x) = 3s^2+28s+55 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -2.8107\\[1 em]s_2 &= -6.5226 \end{aligned} $$Explanation
The solutions of $ 3s^2+28s+55 = 0 $ are: $ s = -\dfrac{ 14 }{ 3 }-\dfrac{\sqrt{ 31 }}{ 3 } ~ \text{and} ~ s = -\dfrac{ 14 }{ 3 }+\dfrac{\sqrt{ 31 }}{ 3 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator