The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= 0\\[1 em]m_2 &= 2 \end{aligned} $$Step 1:
Factor out $ \color{blue}{ 3m^2 }$ from $ 3m^3-6m^2 $ and solve two separate equations:
$$ \begin{aligned} 3m^3-6m^2 & = 0\\[1 em] \color{blue}{ 3m^2 }\cdot ( m-2 ) & = 0 \\[1 em] \color{blue}{ 3m^2 = 0} ~~ \text{or} ~~ m-2 & = 0 \end{aligned} $$One solution is $ \color{blue}{ m = 0 } $. Use second equation to find the remaining roots.
Step 2:
To find the last zero, solve equation $ m-2 = 0 $
$$ \begin{aligned} m-2 & = 0 \\[1 em] m & = 2 \end{aligned} $$