Question
Find roots of polynomial $$ p(x) = 36x^2-72x-1100 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 6.6174\\[1 em]x_2 &= -4.6174 \end{aligned} $$Explanation
The solutions of $ 36x^2-72x-1100 = 0 $ are: $ x = 1-\dfrac{ 2 \sqrt{ 71}}{ 3 } ~ \text{and} ~ x = 1+\dfrac{ 2 \sqrt{ 71}}{ 3 }$.
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