Question
Find roots of polynomial $$ p(x) = 30s^2+102s+24 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -0.2543\\[1 em]s_2 &= -3.1457 \end{aligned} $$Explanation
The solutions of $ 30s^2+102s+24 = 0 $ are: $ s = -\dfrac{ 17 }{ 10 }-\dfrac{\sqrt{ 209 }}{ 10 } ~ \text{and} ~ s = -\dfrac{ 17 }{ 10 }+\dfrac{\sqrt{ 209 }}{ 10 }$.
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