Question
Find roots of polynomial $$ p(x) = 2x^2+8x+13 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -2+\dfrac{\sqrt{ 10 }}{ 2 }i\\[1 em]x_2 &= -2- \dfrac{\sqrt{ 10 }}{ 2 }i \end{aligned} $$Explanation
The solutions of $ 2x^2+8x+13 = 0 $ are: $ x = -2+\dfrac{\sqrt{ 10 }}{ 2 }i ~ \text{and} ~ x = -2-\dfrac{\sqrt{ 10 }}{ 2 }i$.
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