Question
Find roots of polynomial $$ p(x) = 2x^2+720x-\frac{92}{47} $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.0027\\[1 em]x_2 &= -360.0027 \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 47 } $.
$$ \begin{aligned} 2x^2+720x-\frac{92}{47} & = 0 ~~~ / \cdot \color{blue}{ 47 } \\[1 em] 94x^2+33840x-92 & = 0 \end{aligned} $$Step 2:
The solutions of $ 94x^2+33840x-92 = 0 $ are: $ x = -180-\dfrac{\sqrt{ 71573762 }}{ 47 } ~ \text{and} ~ x = -180+\dfrac{\sqrt{ 71573762 }}{ 47 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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