Question
Find roots of polynomial $$ p(x) = 2x^2-32x+256 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 8+8i\\[1 em]x_2 &= 8-8i \end{aligned} $$Explanation
The solutions of $ 2x^2-32x+256 = 0 $ are: $ x = 8+8i ~ \text{and} ~ x = 8-8i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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