Question
Find roots of polynomial $$ p(x) = 2s^2-4s+10 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= 1+2i\\[1 em]s_2 &= 1-2i \end{aligned} $$Explanation
The solutions of $ 2s^2-4s+10 = 0 $ are: $ s = 1+2i ~ \text{and} ~ s = 1-2i$.
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