Question
Find roots of polynomial $$ p(x) = 2d^9 $$
Answer
The root of polynomial $ p(d) $ is:
$$ \begin{aligned}d &= 0 \end{aligned} $$Explanation
$$ \begin{aligned} 2d^9 & = 0 \\[1 em] x & = 0 \end{aligned} $$
Multiplicity of this zero is equal to 9.
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