Question
Find roots of polynomial $$ p(x) = 2a^2+8a+44 $$
Answer
The roots of polynomial $ p(a) $ are:
$$ \begin{aligned}a_1 &= -2+3 \sqrt{ 2 }i\\[1 em]a_2 &= -2-3 \sqrt{ 2 }i \end{aligned} $$Explanation
The solutions of $ 2a^2+8a+44 = 0 $ are: $ a = -2+3 \sqrt{ 2 }i ~ \text{and} ~ a = -2-3 \sqrt{ 2 }i$.
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