Question
Find roots of polynomial $$ p(x) = 27x^2+56x-4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.0691\\[1 em]x_2 &= -2.1432 \end{aligned} $$Explanation
The solutions of $ 27x^2+56x-4 = 0 $ are: $ x = -\dfrac{ 28 }{ 27 }-\dfrac{ 2 \sqrt{ 223}}{ 27 } ~ \text{and} ~ x = -\dfrac{ 28 }{ 27 }+\dfrac{ 2 \sqrt{ 223}}{ 27 }$.
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