Question
Find roots of polynomial $$ p(x) = 25x^2+426x+5248 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -\dfrac{ 213 }{ 25 }+\dfrac{\sqrt{ 85831 }}{ 25 }i\\[1 em]x_2 &= -\dfrac{ 213 }{ 25 }- \dfrac{\sqrt{ 85831 }}{ 25 }i \end{aligned} $$Explanation
The solutions of $ 25x^2+426x+5248 = 0 $ are: $ x = -\dfrac{ 213 }{ 25 }+\dfrac{\sqrt{ 85831 }}{ 25 }i ~ \text{and} ~ x = -\dfrac{ 213 }{ 25 }-\dfrac{\sqrt{ 85831 }}{ 25 }i$.
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