Question
Find roots of polynomial $$ p(x) = 253x^2+825x+630 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.2203\\[1 em]x_2 &= -2.0406 \end{aligned} $$Explanation
The solutions of $ 253x^2+825x+630 = 0 $ are: $ x = -\dfrac{ 75 }{ 46 }-\dfrac{ 3 \sqrt{ 4785}}{ 506 } ~ \text{and} ~ x = -\dfrac{ 75 }{ 46 }+\dfrac{ 3 \sqrt{ 4785}}{ 506 }$.
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