Question
Find roots of polynomial $$ p(x) = 20x^2+180x-567 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.4714\\[1 em]x_2 &= -11.4714 \end{aligned} $$Explanation
The solutions of $ 20x^2+180x-567 = 0 $ are: $ x = -\dfrac{ 9 }{ 2 }-\dfrac{ 9 \sqrt{ 15}}{ 5 } ~ \text{and} ~ x = -\dfrac{ 9 }{ 2 }+\dfrac{ 9 \sqrt{ 15}}{ 5 }$.
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