Question
Find roots of polynomial $$ p(x) = 20x^2-96x-117 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 5.8073\\[1 em]x_2 &= -1.0073 \end{aligned} $$Explanation
The solutions of $ 20x^2-96x-117 = 0 $ are: $ x = \dfrac{ 12 }{ 5 }-\dfrac{ 3 \sqrt{ 129}}{ 10 } ~ \text{and} ~ x = \dfrac{ 12 }{ 5 }+\dfrac{ 3 \sqrt{ 129}}{ 10 }$.
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