Question
Find roots of polynomial $$ p(x) = 20x^2-60x+51 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 30 }}{ 10 }i\\[1 em]x_2 &= \dfrac{ 3 }{ 2 }- \dfrac{\sqrt{ 30 }}{ 10 }i \end{aligned} $$Explanation
The solutions of $ 20x^2-60x+51 = 0 $ are: $ x = \dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 30 }}{ 10 }i ~ \text{and} ~ x = \dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 30 }}{ 10 }i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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