Question
Find roots of polynomial $$ p(x) = 20062x+118709 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\dfrac{ 118709 }{ 20062 } \end{aligned} $$Explanation
$$ \begin{aligned} 20062x+118709 & = 0 \\[1 em]
20062 \cdot x & = -118709 \\[1 em]
x & = - \frac{ 118709 }{ 20062 }
\end{aligned} $$
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