Question
Find roots of polynomial $$ p(x) = 20-\frac{40}{2}-x^2 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= 0 \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 2 } $.
$$ \begin{aligned} 20-\frac{40}{2}-x^2 & = 0 ~~~ / \cdot \color{blue}{ 2 } \\[1 em] \cancel{40} -\cancel{40}-2x^2 & = 0 \end{aligned} $$Step 2:
Combine like terms:
$$ \, \color{blue}{ \cancel{40}} \, \, \color{blue}{ -\cancel{40}} \,-2x^2 = -2x^2 $$Step 3:
$$ \begin{aligned} -2x^2 & = 0 \\[1 em] x & = 0 \end{aligned} $$Multiplicity of this zero is equal to 2.
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