The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 5.4495\\[1 em]x_2 &= 0.5505 \end{aligned} $$Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 3 } $.
$$ \begin{aligned} \frac{2}{3}x^2-4x+2 & = 0 ~~~ / \cdot \color{blue}{ 3 } \\[1 em] 2x^2-12x+6 & = 0 \end{aligned} $$Step 2:
The solutions of $ 2x^2-12x+6 = 0 $ are: $ x = 3-\sqrt{ 6 } ~ \text{and} ~ x = 3+\sqrt{ 6 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.