Question
Find roots of polynomial $$ p(x) = 18x+12 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\dfrac{ 2 }{ 3 } \end{aligned} $$Explanation
$$ \begin{aligned} 18x+12 & = 0 \\[1 em]
18 \cdot x & = -12 \\[1 em]
x & = - \frac{ 12 }{ 18 } \\[1 em]
x & = - \frac{ 12 : 6 }{ 18 : 6} \\[1 em]
x & = -\frac{ 2 }{ 3 }
\end{aligned} $$
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