Question
Find roots of polynomial $$ p(x) = 18x-9 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= \dfrac{ 1 }{ 2 } \end{aligned} $$Explanation
$$ \begin{aligned} 18x-9 & = 0 \\[1 em]
18 \cdot x & = 9 \\[1 em]
x & = \frac{ 9 }{ 18 } \\[1 em]
x & = \frac{ 9 : 9 }{ 18 : 9} \\[1 em]
x & = \frac{ 1 }{ 2 }
\end{aligned} $$
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