Question
Find roots of polynomial $$ p(x) = 16t^2-32t+18 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 1+\dfrac{\sqrt{ 2 }}{ 4 }i\\[1 em]t_2 &= 1- \dfrac{\sqrt{ 2 }}{ 4 }i \end{aligned} $$Explanation
The solutions of $ 16t^2-32t+18 = 0 $ are: $ t = 1+\dfrac{\sqrt{ 2 }}{ 4 }i ~ \text{and} ~ t = 1-\dfrac{\sqrt{ 2 }}{ 4 }i$.
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