Question
Find roots of polynomial $$ p(x) = 12x+26 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\dfrac{ 13 }{ 6 } \end{aligned} $$Explanation
$$ \begin{aligned} 12x+26 & = 0 \\[1 em]
12 \cdot x & = -26 \\[1 em]
x & = - \frac{ 26 }{ 12 } \\[1 em]
x & = - \frac{ 26 : 2 }{ 12 : 2} \\[1 em]
x & = -\frac{ 13 }{ 6 }
\end{aligned} $$
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