Question
Find roots of polynomial $$ p(x) = 12x^2+72x $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= -6 \end{aligned} $$Explanation
Step 1:
Factor out $ \color{blue}{ 12x }$ from $ 12x^2+72x $ and solve two separate equations:
$$ \begin{aligned} 12x^2+72x & = 0\\[1 em] \color{blue}{ 12x }\cdot ( x+6 ) & = 0 \\[1 em] \color{blue}{ 12x = 0} ~~ \text{or} ~~ x+6 & = 0 \end{aligned} $$One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.
Step 2:
To find the second zero, solve equation $ x+6 = 0 $
$$ \begin{aligned} x+6 & = 0 \\[1 em] x & = -6 \end{aligned} $$This page was created using
Polynomial Roots Calculator