Question
Find roots of polynomial $$ p(x) = 12t^2-44t+11 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 3.3968\\[1 em]t_2 &= 0.2699 \end{aligned} $$Explanation
The solutions of $ 12t^2-44t+11 = 0 $ are: $ t = \dfrac{ 11 }{ 6 }-\dfrac{\sqrt{ 22 }}{ 3 } ~ \text{and} ~ t = \dfrac{ 11 }{ 6 }+\dfrac{\sqrt{ 22 }}{ 3 }$.
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