Question
Find roots of polynomial $$ p(x) = \frac{125}{1000}m^2+100m+20000 $$
Answer
The root of polynomial $ p(m) $ is:
$$ \begin{aligned}m &= -400 \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 1000 } $.
$$ \begin{aligned} \frac{125}{1000}m^2+100m+20000 & = 0 ~~~ / \cdot \color{blue}{ 1000 } \\[1 em] 125m^2+100000m+20000000 & = 0 \end{aligned} $$Step 2:
The solution of $ ~ 125m^2+100000m+20000000 = 0 ~$ is $~ m = -400 ~$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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