Question
Find roots of polynomial $$ p(x) = 112x+390 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\dfrac{ 195 }{ 56 } \end{aligned} $$Explanation
$$ \begin{aligned} 112x+390 & = 0 \\[1 em]
112 \cdot x & = -390 \\[1 em]
x & = - \frac{ 390 }{ 112 } \\[1 em]
x & = - \frac{ 390 : 2 }{ 112 : 2} \\[1 em]
x & = -\frac{ 195 }{ 56 }
\end{aligned} $$
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