Question
Find roots of polynomial $$ p(x) = 10k^2+9k-1 $$
Answer
The roots of polynomial $ p(k) $ are:
$$ \begin{aligned}k_1 &= \dfrac{ 1 }{ 10 }\\[1 em]k_2 &= -1 \end{aligned} $$Explanation
The solutions of $ 10k^2+9k-1 = 0 $ are: $ k = -1 ~ \text{and} ~ k = \dfrac{ 1 }{ 10 }$.
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