Question
Find roots of polynomial $$ p(x) = 1-x+\frac{3}{16}x^2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4\\[1 em]x_2 &= \dfrac{ 4 }{ 3 } \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 16 } $.
$$ \begin{aligned} 1-x+\frac{3}{16}x^2 & = 0 ~~~ / \cdot \color{blue}{ 16 } \\[1 em] 16-16x+3x^2 & = 0 \end{aligned} $$Step 2:
Write polynomial in descending order
$$ \begin{aligned} 16-16x+3x^2 & = 0\\[1 em] 3x^2-16x+16 & = 0 \end{aligned} $$Step 3:
The solutions of $ 3x^2-16x+16 = 0 $ are: $ x = \dfrac{ 4 }{ 3 } ~ \text{and} ~ x = 4$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator