Question
Find roots of polynomial $$ p(x) = -11x+8 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= \dfrac{ 8 }{ 11 } \end{aligned} $$Explanation
$$ \begin{aligned} -11x+8 & = 0 \\[1 em]
-11 \cdot x & = -8 \\[1 em]
x & = - \frac{ 8 }{ -11 } \\[1 em]
x & = \frac{ 8 }{ 11 }
\end{aligned} $$
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