Question
Find roots of polynomial $$ p(x) = -66x^2-260+98x $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \dfrac{ 49 }{ 66 }+\dfrac{\sqrt{ 14759 }}{ 66 }i\\[1 em]x_2 &= \dfrac{ 49 }{ 66 }- \dfrac{\sqrt{ 14759 }}{ 66 }i \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} -66x^2-260+98x & = 0\\[1 em] -66x^2+98x-260 & = 0 \end{aligned} $$Step 2:
The solutions of $ -66x^2+98x-260 = 0 $ are: $ x = \dfrac{ 49 }{ 66 }+\dfrac{\sqrt{ 14759 }}{ 66 }i ~ \text{and} ~ x = \dfrac{ 49 }{ 66 }-\dfrac{\sqrt{ 14759 }}{ 66 }i$.
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