Question
Find roots of polynomial $$ p(x) = -62x^2+62x+900 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.3427\\[1 em]x_2 &= -3.3427 \end{aligned} $$Explanation
The solutions of $ -62x^2+62x+900 = 0 $ are: $ x = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 56761 }}{ 62 } ~ \text{and} ~ x = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 56761 }}{ 62 }$.
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