Question
Find roots of polynomial $$ p(x) = -49x^2+490x-985 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 7.2131\\[1 em]x_2 &= 2.7869 \end{aligned} $$Explanation
The solutions of $ -49x^2+490x-985 = 0 $ are: $ x = 5-\dfrac{ 4 \sqrt{ 15}}{ 7 } ~ \text{and} ~ x = 5+\dfrac{ 4 \sqrt{ 15}}{ 7 }$.
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