Question
Find roots of polynomial $$ p(x) = -3+\frac{8}{6} $$
Answer
Polynomial $ p(x) $ has no zeros.
Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 6 } $.
$$ \begin{aligned} -3+\frac{8}{6} & = 0 ~~~ / \cdot \color{blue}{ 6 } \\[1 em] -18+8 & = 0 \end{aligned} $$Step 2:
Combine like terms:
$$ \color{blue}{-18} + \color{blue}{8} = \color{blue}{-10} $$Step 3:
Equation $ -10 = 0 $ has no solutions.
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