Question
Find roots of polynomial $$ p(x) = -2x^2+2x+13 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 3.0981\\[1 em]x_2 &= -2.0981 \end{aligned} $$Explanation
The solutions of $ -2x^2+2x+13 = 0 $ are: $ x = \dfrac{ 1 }{ 2 }-\dfrac{ 3 \sqrt{ 3}}{ 2 } ~ \text{and} ~ x = \dfrac{ 1 }{ 2 }+\dfrac{ 3 \sqrt{ 3}}{ 2 }$.
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