Question
Find roots of polynomial $$ p(x) = -2v^2+3v^2+1 $$
Answer
The roots of polynomial $ p(v) $ are:
$$ \begin{aligned}v_1 &= i\\[1 em]v_2 &= -i \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ \color{blue}{-2v^2} + \color{blue}{3v^2} +1 = \color{blue}{v^2} +1 $$Step 2:
The solutions of $ v^2+1 = 0 $ are: $ v = i ~ \text{and} ~ v = -i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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