Question
Find roots of polynomial $$ p(x) = -18x^2-29x+15 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.4119\\[1 em]x_2 &= -2.023 \end{aligned} $$Explanation
The solutions of $ -18x^2-29x+15 = 0 $ are: $ x = -\dfrac{ 29 }{ 36 }-\dfrac{\sqrt{ 1921 }}{ 36 } ~ \text{and} ~ x = -\dfrac{ 29 }{ 36 }+\dfrac{\sqrt{ 1921 }}{ 36 }$.
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