Question
Find roots of polynomial $$ p(x) = -16p+400 $$
Answer
The root of polynomial $ p(p) $ is:
$$ \begin{aligned}p &= 25 \end{aligned} $$Explanation
$$ \begin{aligned} -16p+400 & = 0 \\[1 em]
-16 \cdot p & = -400 \\[1 em]
p & = - \frac{ 400 }{ -16 } \\[1 em]
p & = - \frac{ 400 : 16 }{ -16 : 16} \\[1 em]
p & = 25
\end{aligned} $$
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