Question
Find roots of polynomial $$ p(x) = -12+16i $$
Answer
The root of polynomial $ p(i) $ is:
$$ \begin{aligned}i &= \dfrac{ 3 }{ 4 } \end{aligned} $$Explanation
$$ \begin{aligned} -12+16i & = 0 \\[1 em]
16 \cdot i & = 12 \\[1 em]
i & = \frac{ 12 }{ 16 } \\[1 em]
i & = \frac{ 12 : 4 }{ 16 : 4} \\[1 em]
i & = \frac{ 3 }{ 4 }
\end{aligned} $$
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