Question
$$x^6+104x^4+400x^2 = 0$$
Answer
$$ x = 0 $$
Explanation
In order to solve $ \color{blue}{ x^{6}+104x^{4}+400x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ x^{6}+104x^{4}+400x^{2} = x^2 \left( x^{4}+104x^{2}+400 \right) $$$ x = 0 $ is a root of multiplicity $ 2 $.
The remaining roots can be found by solving equation $ x^{4}+104x^{2}+400 = 0$.
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
This page was created using
Polynomial Equations Solver