Question
$$9(w^2-13)(w^2+3) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 9(w^2-13)(w^2+3) &= 0&& \text{simplify left side} \\[1 em](9w^2-117)(w^2+3) &= 0&& \\[1 em]9w^4+27w^2-117w^2-351 &= 0&& \\[1 em]9w^4-90w^2-351 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
This page was created using
Polynomial Equations Solver