In order to solve $ \color{blue}{ -x^{5}+6x^{3}+2x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ -x^{5}+6x^{3}+2x^{2} = x^2 \left( -x^{3}+6x+2 \right) $$$ x = 0 $ is a root of multiplicity $ 2 $.
The remaining roots can be found by solving equation $ -x^{3}+6x+2 = 0$.
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.