Question
$$(b^2+5)(-b^2+7) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (b^2+5)(-b^2+7) &= 0&& \text{simplify left side} \\[1 em]-b^4+7b^2-5b^2+35 &= 0&& \\[1 em]-b^4+2b^2+35 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
This page was created using
Polynomial Equations Solver