The equation of the line parallel to the given line that contains point $ A $ is:
$ \color{blue}{ 5x+7y+10=0 }$ ( General form )
$ \color{blue}{ y = - \frac{ 5 }{ 7 } x - \frac{ 10 }{ 7 } } ~~~$ ( Slope y-intercept form )
Step 1:The slope of a given line is $ m = -\frac{ 5 }{ 7 } $.
Step 2: Parallel lines have the same slope, so the slope of the unknown line ($ m_1 $) will also be $ -\frac{ 5 }{ 7 } $. So the parallel line will have a slope of $ m_1 = -\frac{ 5 }{ 7 } $
Step 3: Now we have a point and the slope so we can use point-slope form, which is:
$$ y - y_0 = m_1 (x - x_0) $$In this example we have: $ m_1 = -\frac{ 5 }{ 7 } $ , $ x_0 = -9 $ and $ y_0 = 5 $. After substitution we have:
$$ \begin{aligned} y - y_0 =& ~ m_1 (x - x_0) \\ y - 5 =& ~ -\frac{ 5 }{ 7 } ( x - \left( -9\right)) \\y -5 =& ~ -\frac{ 5 }{ 7 } x -\frac{ 45 }{ 7 } \\y =& ~ -\frac{ 5 }{ 7 } x -\frac{ 45 }{ 7 } + 5 \\y =& ~ - \frac{ 5 }{ 7 } x - \frac{ 10 }{ 7 }\\ \end{aligned} $$